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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm' q5 {- a4 ?+ V2 P! v) z
原始出处:http://www.3ast.com.cm
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看不懂的直接绕过
$ a; F7 @& Y% A }! b+ L加密前为:hwy123456
: D* m% e# ~, [$ V" c. d$ K加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
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============================================) X. R) }* V- G, T/ Z# P1 g7 A& n
上面是当时自己校内的心情。现在已经解破出来了,分享给大家
& B( y1 y2 r( X8 C/ `$ W也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法) o( G( j \, W: {! P0 D
以下是RSA算法文件6 [/ M+ T. t' _0 t" q: \. t
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文件名RSA.ASP
( o2 R# Y8 {3 O4 ^7 J===============================================
3 }. V" O/ P, }6 {3 j5 p( ?) {<%
9 P" K) i5 C8 q7 O" P' hClass clsRSA
$ U% A; \: l' S1 ?- lPublic PrivateKey
$ C- {& U; v6 q3 _; jPublic PublicKey ) ~# `+ V5 s! a% O8 k4 U# e
Public Modulus
3 @$ P& K$ i1 a, t2 h! OPublic Function Crypt(pLngMessage, pLngKey) ( N% v0 g9 y0 b& u
On Error Resume Next . ^% j% X- z& D% Z4 X. f$ _
Dim lLngMod
! E" c; x; g4 J/ V3 XDim lLngResult
1 \5 m' K" i+ D4 l L4 u7 sDim lLngIndex 0 z" K# }( T6 f& b1 X$ C
If pLngKey Mod 2 = 0 Then 1 D$ E1 t* f' _5 @0 N' i
lLngResult = 1 ! J1 \9 {/ J# ^, X% z& ?% ~
For lLngIndex = 1 To pLngKey / 2 ) M, L# ]0 n/ X" ?- J" b$ c
lLngMod = (pLngMessage ^ 2) Mod Modulus : d i9 Q( _1 R
' Mod may error on key generation ) ]5 P3 s! r" }9 l! B
lLngResult = (lLngMod * lLngResult) Mod Modulus % j" h$ [6 c# k- c
If Err Then Exit Function % r: A' J2 t) L, W& U
Next
- C1 }& d& Y/ {Else / d; U9 q r+ Z5 H# d
lLngResult = pLngMessage
5 W0 H' f+ N& s* B+ t& uFor lLngIndex = 1 To pLngKey / 2
; Z" k W$ }) o* g" K) Q& WlLngMod = (pLngMessage ^ 2) Mod Modulus
: m2 u4 b, W$ kOn Error Resume Next " }9 }: p% X7 u. o* }7 f+ R( m
' Mod may error on key generation
5 O; \4 h6 t- k# AlLngResult = (lLngMod * lLngResult) Mod Modulus 1 n+ }$ `! {- O' }
If Err Then Exit Function & r% G8 z6 a- b7 J! c! D, w9 W$ {0 v
Next
1 v6 O. c) U6 a r, U$ MEnd If
1 ?4 ?8 A+ N# t% A, _7 [% N' p# a" zCrypt = lLngResult 2 l$ d% M" ?3 r2 M
End Function/ c' w5 u' y6 j
, m7 A4 B3 E6 d6 _+ l* ]( }Public Function Encode(ByVal pStrMessage) / b4 r6 W z$ D9 ~. [7 ~
Dim lLngIndex 0 _* E5 o5 i5 y) s; L6 s0 A
Dim lLngMaxIndex
( v1 F5 t; O( P4 m zDim lBytAscii
# @& Q2 z/ K& b f: }Dim lLngEncrypted , d" @' R/ _0 z& x# _# r) _0 h
lLngMaxIndex = Len(pStrMessage)
( S6 W, J. D/ z6 Q/ _* n0 d+ c* dIf lLngMaxIndex = 0 Then Exit Function
- K) t/ h- k8 J: HFor lLngIndex = 1 To lLngMaxIndex + b( @; T6 @. \# }
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) ; Y/ a5 \+ ?( G I( A
lLngEncrypted = Crypt(lBytAscii, PublicKey)
8 P! ?; R2 U0 t J- TEncode = Encode & NumberToHex(lLngEncrypted, 4) 5 p5 X6 G, H1 W
Next
8 P1 t* f9 N% U( r- mEnd Function
5 c+ f; C; Q0 C1 \ t# V% vPublic Function Decode(ByVal pStrMessage)
& e4 v2 ^' `, U" g' zDim lBytAscii
% m; w+ p3 {+ ?) l mDim lLngIndex 9 N, ^; w0 E7 m, s/ ^" \% p: v# N
Dim lLngMaxIndex , h6 H5 e1 Q3 J
Dim lLngEncryptedData , E" Y$ D0 W, a* J* `
Decode = "" % A; n# t+ Z0 ]2 m1 \4 x
lLngMaxIndex = Len(pStrMessage) 8 h. m8 A+ K4 c% N; H
For lLngIndex = 1 To lLngMaxIndex Step 4 ( O1 J$ p1 x1 e0 R" a
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
' K: e% C' D% W2 LlBytAscii = Crypt(lLngEncryptedData, PrivateKey)
. J4 Y0 v6 m) {. GDecode = Decode & Chr(lBytAscii)
; U: r2 l0 }0 L+ M" r7 t6 bNext
v; O( c: m2 t8 v2 {& V. [( uEnd Function 7 n) l* W" b2 v4 J- X) s5 S
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) 4 U. k+ _8 E+ K8 s- Q) q
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
7 | w; K6 C+ nEnd Function
1 \( r% v! O5 U9 y! j1 y E0 [Private Function HexToNumber(ByRef pStrHex)
8 r. e7 j$ [! OHexToNumber = CLng("&h" & pStrHex) # ^, ?! }. O. ~0 V) ^" O) [' M) ~/ G
End Function
8 ^ I* k' [9 t: E1 @6 \* u8 b2 ?# SEnd Class / F3 l, }$ h; }: B, o0 [
function Encryptstr(Message) ( k' @& w1 x8 U, I5 s7 O
Dim LngKeyE # Y3 s7 a8 ]' Q4 g) P% d4 A# j
Dim LngKeyD 2 e2 U1 N, N: x _/ p* r# g+ j
Dim LngKeyN
# q4 D! `: e( ~5 O& p" qDim StrMessage " Q0 R3 [$ G, F: D; V+ y E
Dim ObjRSA $ _. r% w: N5 U0 ^+ o
LngKeyE = "32823"
% V4 P* {8 R) J' S2 D3 C) n' ALngKeyD = "20643" , t4 S* |! M, K+ A2 `& G" Y
LngKeyN = "29893" / u4 s" g9 e! Y' j) a. u* O
StrMessage = Message
1 M3 O- ]. r4 J0 j) a$ H! @Set ObjRSA = New clsRSA * \& y' [- V) o9 U1 D8 M2 \
ObjRSA.PublicKey = LngKeyE
8 ~) D8 u) `" b i! bObjRSA.Modulus = LngKeyN 3 o; o- Y4 r) D x5 A6 O1 p
Encryptstr = ObjRSA.Encode(StrMessage)
; X" V: S9 S! t% g# _0 M/ A& S' q& uSet ObjRSA = Nothing
+ W6 B; ?* X7 @1 o$ Wend function
" |# D( E O( n. q! @Function Decryptstr(Message)
4 U# \; N Y' P0 W7 ODim LngKeyE * v& _" K! E8 |" n
Dim LngKeyD
% S! h; G, K, S* w+ d: j% T2 IDim LngKeyN ( {, p7 b+ K; s9 q, _7 ?5 y% ^
Dim StrMessage
1 Z/ M/ Q- K s: D, }( A6 a* P# YDim ObjRSA G5 _8 X' G2 K; y, B4 o3 \/ G& a$ Z
LngKeyE = "32823" # Y/ C" Q0 x& l u& V
LngKeyD = "20643"
5 v: }6 c+ T" d4 [LngKeyN = "29893"
- I/ T4 [4 j) C) _: OStrMessage = Message + h2 R1 D5 i, d/ `
Set ObjRSA = New clsRSA
' C1 c# F9 e% K3 M; k2 q$ BObjRSA.PrivateKey =LngKeyD 8 ^# C2 v8 q/ N$ m7 M" [
ObjRSA.Modulus=LngKeyN % p; |5 N$ a3 n1 |' g f$ F
decryptstr=ObjRSA.Decode(StrMessage) 6 {! T. A5 B8 H0 s8 B H0 ?
Set ObjRSA = Nothing 6 ]/ q& j# ?# ]0 T, U8 S
end function . o+ w f3 [: p5 f5 e% J# N3 s
%>/ J) G! |( {: x( `3 o ]
===============================================
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还有一个用于测试这段代码的test.asp
, O( h5 C1 h0 Z2 F有兴趣的自己搭建个IIS测试下
- I7 _; a4 b4 \' i& ?6 z<!--#INCLUDE FILE="RSA.asp"-->
* ~0 J1 v3 \. i4 p! c1 |<%
2 m4 \6 s. z5 ~# i. xfunction Encryptstr(Message)
; s4 _ R1 o% W- F; `Dim LngKeyE
4 @/ ?7 D3 Z1 l7 v7 @9 z6 QDim LngKeyD
u7 E+ W* w5 c# F I" J8 x9 @Dim LngKeyN 4 t5 M7 I7 t, k% P0 S' x
Dim StrMessage
! x: F. n! ]+ I0 _( c% F8 I5 {Dim ObjRSA
1 E4 n9 }1 y3 F( s& TLngKeyE = "32823"
# L8 x; _- e# H) \LngKeyD = "20643"
3 X9 s o- F1 XLngKeyN = "29893"
9 E M" E% \) @+ A( q3 u: I$ ]StrMessage = Message : E/ ]5 Q6 c) }# v, ]" y4 N! V
Set ObjRSA = New clsRSA
" ^5 t* Y! q( I8 a9 GObjRSA.PublicKey = LngKeyE
' O7 M4 }% _8 ^" d+ p1 mObjRSA.Modulus = LngKeyN ' ?$ L& O, M" N" G: a" T
Encryptstr = ObjRSA.Encode(StrMessage)
4 F6 W. A5 `& `$ H, C( P0 dSet ObjRSA = Nothing , d8 D/ M T& N, J9 M
end function
0 J m; a) }$ n4 kfunction decryptstr(Message)
1 \0 C2 f/ ?- i K" a5 dDim LngKeyE 6 @& J4 N6 [5 H, K7 @4 Z) P# O
Dim LngKeyD
" D* x, G, Z" ]7 W2 Y# f& GDim LngKeyN
R4 z. o- q* |+ V2 p/ O( xDim StrMessage
6 p; {1 u) f; o" r* kDim ObjRSA 5 W* @: K3 p( @8 A* l9 D: E
LngKeyE = "32823" 0 F; e0 T. N! Q& m
LngKeyD = "20643" 3 ?: B4 N0 a! z3 o ?: m
LngKeyN = "29893"
" l; j- g, ]5 [: ? C" b4 WStrMessage = Message
0 r/ u: P1 C+ a: kSet ObjRSA = New clsRSA ( s7 n5 R% k; O3 {3 b6 F0 o
ObjRSA.PrivateKey =LngKeyD
+ g4 x0 L8 }0 u U! j! B0 YObjRSA.Modulus=LngKeyN
1 P' C8 o- u7 Y2 L4 _3 Idecryptstr=ObjRSA.Decode(StrMessage) / ^- H3 D* d0 s8 s% A; M
Set ObjRSA = Nothing
; @; l, s8 b" E7 w# M9 Iend function
& L7 Z- H: Z" E9 I# ?) `& Y1 jdim last,first ' Q& F! X, q/ _! b! R
first="!@#$%^&*()" ' _# L( W. g5 N# ], z6 P8 y' ?/ H
Response.Write "加密前为:"&first # o( G8 a) `5 i7 A
last=Encryptstr(first)
0 c4 B: F3 S! w# h& V7 @2 mResponse.Write "加密后为"&last
0 C" |; ?' q% y& I: ?Response.Write "解密后为" &decryptstr(last) / y3 @( |7 W! @3 n9 Q* `
%> ==============================================2 e9 ?: j* G1 a+ t
剩下的就是字符的对照表了7 B. U+ y/ ~8 a/ u( S0 J
===================字符集================
5 ]( C' q7 i6 k2 ^1_____6EBB {- Y# g, X' r, g7 F& _5 m
2_____5C1F
6 ^0 s* b9 k7 j- m3_____4D75* H- f7 C2 r8 x1 w$ s0 I" v
4_____26CC
! g1 w6 [" l) x3 }5_____4F888 t. m( @5 p& Y
6_____3F4E2 I4 B* J9 X5 }$ K
7_____0A9D( x9 F3 m& b i& }& S1 S8 u
8_____1A1C
0 s7 z, F8 {% U+ V I9_____6D20: T' c- ~4 U) e \! c1 A+ \+ Q) ?7 z% x
0_____1089( Q6 H( }7 p! {/ p: I
a_____0F3E
8 F& @8 e7 K9 C) I, |. `b_____31592 R; z9 n7 Z- [1 l# O1 h
c_____35170 B) s4 E6 y( Z8 c9 K# F, A
d_____419C3 |* A# O, o* @- K" w8 J
e_____615C
0 O: c5 b& x$ k# A( Kf_____556F& e8 M% Q9 L+ u, \1 q' H
g_____2B7F
* ?8 x+ \ o( X v3 L7 ~h_____0F9C0 b1 ]/ ~! m( ^9 U& _
i_____00FA8 `* u% v6 N% d
j_____5A50
) F* n* W4 H U6 U; ek_____2850
. B3 t6 `. r7 ?1 Q5 r% h4 I/ bl_____3E7B
5 m( T7 ]$ n) M4 h6 j) Pm_____71C5
! f0 r4 v/ b: j7 F) V' p$ nn_____1FC8# m5 B; M, R, J
o_____74C16 B& |; d) H7 I" q5 M) q, B
p_____5FB87 a; a4 V& d' D3 l
q_____60851 x9 l$ x' B6 ~
r_____3AC4
) X* k3 E$ r- [s_____2F50
0 Q5 r4 @3 N G/ a9 L- xt_____36F8' f: d f$ k- t, e& @
u_____7010! }5 s& Z; @9 X4 L3 m/ f% P @# g4 f
v_____0B42$ {* @4 r) x2 M q8 |% J! h
w_____1C7A
. ^% Y: a# q$ D) |x_____16F85 x# f+ H' T: @9 E
y_____2EE74 h3 Y7 Q* f- o
z_____5CF3& x0 W" M3 g* \: j: ~% V
!_____6233
( K; X2 Q1 c; z2 i4 o6 Q@_____3A45
: e1 i% @% w" j+ e0 y! J) a/ R#_____22914 H' H* P' h) B: `6 H
$_____5D5C0 @8 G$ y& R* G
%_____09B9
/ O) \4 h( l- y* ^4 {, r1 Y m^_____43EA: |9 ]/ F$ G# F; A
&_____62B99 R! v) N$ l+ }2 ~
*_____63014 X& q; |) y1 } v
(_____4659
# z) @. K0 i$ J. r k)_____5C82 |
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