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[原创文章] 关于国内某知名大学网站加密算法的研究

原创作者:柔肠寸断 [3.A.S.T]  http://www.3ast.com.cm8 t7 r/ j3 `) S1 h" c1 A
原始出处:http://www.3ast.com.cm
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看不懂的直接绕过
4 K% y. `* _! C6 ]) H; y8 E5 f7 O加密前为:hwy123456
# |) |7 b/ \2 ~加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E( S& t6 s, R5 F+ C2 \8 U) _
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============================================
& X& q( p9 t3 _( y& ]1 ]上面是当时自己校内的心情。现在已经解破出来了,分享给大家
" t1 e, h! p, G; d8 }5 w也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
/ G1 t0 J5 g# U4 t$ }. W) w. N4 P& q9 a以下是RSA算法文件2 X5 ^% i' g& G5 N* |

* e0 x, T5 ?* a4 A文件名RSA.ASP
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<% + W( Z+ r; z3 Y9 e
Class clsRSA - e  [+ T7 Z( A& J
Public PrivateKey 6 T% |$ n, t2 ?+ a' ~& v3 M
Public PublicKey 2 ~' M% T' V0 L! G7 i
Public Modulus 3 M% B- {- E! b" i: V; k( d6 r
Public Function Crypt(pLngMessage, pLngKey)
- I; p$ k( Y# COn Error Resume Next
2 h4 y- G$ {' b( s- q, fDim lLngMod
* Z: M& \7 h, I4 Z, BDim lLngResult / {! e! W" `3 N  B$ M
Dim lLngIndex
+ o. t, H3 a. n. ^2 C! z% x' ~If pLngKey Mod 2 = 0 Then * z5 f9 x! a$ |
lLngResult = 1
, F7 K$ a! o. o! k: M; n" TFor lLngIndex = 1 To pLngKey / 2
4 w. z5 l1 J& s% \/ n5 g8 s# dlLngMod = (pLngMessage ^ 2) Mod Modulus # X, N( Q0 {  h
' Mod may error on key generation   e. d3 P5 U7 I) k  u
lLngResult = (lLngMod * lLngResult) Mod Modulus # K+ v7 t6 n3 `7 ]1 [
If Err Then Exit Function
) h0 Z4 |, @( \1 m0 a8 z$ ONext
4 f( F, t: B! Q& K% s) |0 WElse : p9 {3 S8 h, ^3 W% J4 L+ O8 Y' ?
lLngResult = pLngMessage , T4 [" }# ^4 P9 ~( i
For lLngIndex = 1 To pLngKey / 2
0 k) h# f/ [. I) a, tlLngMod = (pLngMessage ^ 2) Mod Modulus + m$ T7 \+ |2 w3 c* H* Q& J
On Error Resume Next 4 r- p+ Z$ [  ~. s" \% J7 p
' Mod may error on key generation 0 Y' w; n( s1 \3 q2 ?
lLngResult = (lLngMod * lLngResult) Mod Modulus * G& Q( A- K( Z  X. I* y
If Err Then Exit Function 8 _  M- y! ~/ M1 c' J- F& L
Next ! O  l' Q6 z% Y, l4 x* k
End If 8 K3 U) h1 j* @# Y  b/ M
Crypt = lLngResult 3 g5 R  i% ]/ {+ \& K  Z
End Function' k& G* F) L  r4 z8 z% f
: Y1 D# w# g+ I( ^
Public Function Encode(ByVal pStrMessage)
0 g; b, x+ X1 S" d) ?3 |) O* nDim lLngIndex
# f4 m/ q$ u- kDim lLngMaxIndex
/ W; }1 @& [0 R' ^4 _: Z; T2 R, ]Dim lBytAscii - Q# [, ~/ B' c3 d8 [  T% {
Dim lLngEncrypted , j6 V( R: n$ a4 |
lLngMaxIndex = Len(pStrMessage)
9 \: O' S8 t4 X. M1 fIf lLngMaxIndex = 0 Then Exit Function 6 Y# f, P  L- V$ d# f4 x
For lLngIndex = 1 To lLngMaxIndex 7 l5 c) e# R7 E  R* y
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) % G& B) h2 o1 k# M9 @* J! U4 R; F
lLngEncrypted = Crypt(lBytAscii, PublicKey) $ A/ Y, |3 O# Q" }, e5 C& D
Encode = Encode & NumberToHex(lLngEncrypted, 4)
" U, s; Q6 t) m" k2 U% kNext / C0 b2 n7 B" J2 x. e$ X. L
End Function
6 O: M" s4 P9 n, c. TPublic Function Decode(ByVal pStrMessage) 6 @' W) B! W8 b! f( z
Dim lBytAscii
# y1 m: n& [. H5 y1 @1 V1 n) DDim lLngIndex 5 J( T9 w6 L" j; r. w* O
Dim lLngMaxIndex / u. p: Z+ `( q% |* y
Dim lLngEncryptedData
3 T1 j+ p, K7 d2 u7 [. b2 Y. A& j% eDecode = ""
% t* j0 m( Z) L* \& m# b. D7 x7 DlLngMaxIndex = Len(pStrMessage) ' S% K7 K: J$ |) ?! S' N
For lLngIndex = 1 To lLngMaxIndex Step 4
8 s! q6 R3 n8 _  p$ h& s- ]2 J6 xlLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) + A+ \% ^- r: |" I6 S4 _5 Q# _
lBytAscii = Crypt(lLngEncryptedData, PrivateKey)
6 c8 p* I7 ?3 e5 r1 [* ZDecode = Decode & Chr(lBytAscii) 4 G5 P. I1 Q; L
Next
7 S9 R5 A. h3 H4 xEnd Function
. }: K$ l  D) K/ f  r- j8 ePrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
  B# C3 Q: x: a4 CNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) 6 H; |0 B% h1 n0 e7 t
End Function . y' Y7 L: V( W9 `$ D
Private Function HexToNumber(ByRef pStrHex)
6 Y$ z. v* j' g6 @! i8 a% bHexToNumber = CLng("&h" & pStrHex) ) N/ G  u" h* }
End Function
+ O8 R- k( [% ^8 E6 g! OEnd Class
, l4 v6 A. O/ @7 H% Lfunction Encryptstr(Message) 6 ]6 o. _0 c: K3 y$ P8 w$ z* t0 c
Dim LngKeyE
; m  E& y) J0 J- t) K& n! o" mDim LngKeyD 2 X+ q7 s6 D, z" U2 s9 S8 T) U
Dim LngKeyN , i; y8 w3 w; V4 v, Y6 l
Dim StrMessage
7 p* {2 W$ v! [' V# ^; q: b+ QDim ObjRSA
4 ~( i: X& q- S: \$ P- nLngKeyE = "32823"
' L+ N2 ^9 N# m, lLngKeyD = "20643"   L) i5 K6 z: h8 @- Z9 _
LngKeyN = "29893"
9 U+ p7 B# Z$ JStrMessage = Message
5 U* C5 w% _4 B" O5 ^/ _Set ObjRSA = New clsRSA " f6 C, q  k' i7 [& g. {5 A
ObjRSA.PublicKey = LngKeyE
: Y4 b. o+ R' oObjRSA.Modulus = LngKeyN
6 K' x! x- k6 `- m% \/ y& p! ?# ZEncryptstr = ObjRSA.Encode(StrMessage) # h0 U  L9 u) J8 F* Y4 T
Set ObjRSA = Nothing - N7 q/ {; ^, f" _
end function1 N1 l5 D) n1 W% }" z' M
Function Decryptstr(Message) 5 X8 H/ I3 w* O4 x9 \) H+ A
Dim LngKeyE 7 n6 e( K5 l0 t2 `( P
Dim LngKeyD
1 T" k5 V) e7 v: Q+ XDim LngKeyN
; p2 x3 _3 M8 e5 S8 y/ mDim StrMessage
+ @) P2 i$ Y; }Dim ObjRSA
$ w* F& q5 L+ m( sLngKeyE = "32823"
3 O; L: }3 W( g4 A9 j# uLngKeyD = "20643"
; x! g0 Z3 C* j, [* XLngKeyN = "29893" . b: c, H( o( D) y! m# K/ O% A' I) c
StrMessage = Message
4 V% U2 q8 ~5 @) K4 I# tSet ObjRSA = New clsRSA " S! q1 E& F5 S& X9 s! a5 U
ObjRSA.PrivateKey =LngKeyD
( |3 b8 r' [( I& oObjRSA.Modulus=LngKeyN
6 p+ t. E$ y$ x. {- _! Gdecryptstr=ObjRSA.Decode(StrMessage) $ b, \2 o0 U$ w& g$ ^9 ]: i9 ]- B
Set ObjRSA = Nothing
" ?. I. D7 F" m# @  Wend function
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还有一个用于测试这段代码的test.asp% W0 B, Y/ s1 J/ w; v  f
有兴趣的自己搭建个IIS测试下0 r5 E8 [, K9 p8 h) C2 X
<!--#INCLUDE FILE="RSA.asp"-->
  Q, ]3 H+ Z8 B<%
# |; m5 `) {% D! h) n; ifunction Encryptstr(Message) ; R) B9 t0 @& Q8 h% y6 _' c
Dim LngKeyE
. n& N  ?  b  X1 z' s! ?* ADim LngKeyD
) r4 g; I3 K8 W5 {' w+ W( u( `Dim LngKeyN 1 k8 _6 c9 h- x) |$ p
Dim StrMessage
) h- N8 {1 m& HDim ObjRSA
' t: U2 P- G, m+ b% s2 H0 D  Z/ qLngKeyE = "32823" / j5 v7 U; D) A, y% ]& s6 g5 i* V
LngKeyD = "20643" # M- A7 N: S# c5 [0 T8 A
LngKeyN = "29893" $ i0 v/ G+ y$ S8 M$ E6 q
StrMessage = Message . E4 P) z( s8 W- V. T; E' `7 G' [9 f* {
Set ObjRSA = New clsRSA
5 \7 t9 T6 ^- \% Z1 rObjRSA.PublicKey = LngKeyE 0 Q0 R6 c3 J: k( Z* r
ObjRSA.Modulus = LngKeyN
) r) f: E; Y; y( wEncryptstr = ObjRSA.Encode(StrMessage)
: Q( \' N# ~7 M0 YSet ObjRSA = Nothing 5 k5 Z8 s$ p7 R' Y# A9 n
end function : J& X- d6 r: O
function decryptstr(Message)
; m' S+ c6 y" e6 s& E( b; ?Dim LngKeyE % t7 K; i+ H$ n; P: X
Dim LngKeyD
, o% X+ A. V* q* pDim LngKeyN
' d8 U  G* u0 y. W" k1 XDim StrMessage
/ r7 z  p, r8 r, VDim ObjRSA / i& @! ?( v5 }, ?0 d4 G0 D! `
LngKeyE = "32823"
0 N1 I$ n$ q' t) L# P' f) L, CLngKeyD = "20643"
  P5 `4 V8 @1 k9 |- dLngKeyN = "29893" " J4 C9 D, X4 M) O3 j: \; F+ w) H
StrMessage = Message
( T) w7 Z6 q  ~Set ObjRSA = New clsRSA 2 h: j$ G( z: o" k0 S! E3 R  ?- J
ObjRSA.PrivateKey =LngKeyD
" i( n: d+ z! t+ }ObjRSA.Modulus=LngKeyN ! [* n% c' d2 `
decryptstr=ObjRSA.Decode(StrMessage) 8 m! v4 x! H# r3 D3 c
Set ObjRSA = Nothing
# f8 k; L4 U0 o! i0 {# vend function 8 e; X& i* }3 i1 s; N
dim last,first ; g# k; H: c5 @2 V( Q
first="!@#$%^&*()" : I# E" T  _" T2 L
Response.Write "加密前为:"&first
# h+ G/ j. j! I+ ~1 V; X( D" \last=Encryptstr(first) - Z: ~7 Y% Y. ^1 X
Response.Write "加密后为"&last 2 A/ A. T: C: _& _
Response.Write "解密后为" &decryptstr(last)
4 G% f3 q% W* F5 F%> ==============================================
  q# U( [5 N& k8 c( t剩下的就是字符的对照表了
2 X+ i- X8 |' `5 D===================字符集================5 r2 i/ V/ j+ D$ X, S
1_____6EBB- Z/ ], o$ G" Z4 g2 s; P! N) o
2_____5C1F0 n# \) [# i$ E2 [6 q0 U6 D
3_____4D75
: N2 l6 N: s& g' S2 g. Y3 `4_____26CC
- k/ ^- f9 i# A, D5_____4F88
9 b8 b# ]- r/ f! |" L; X6_____3F4E
0 D7 Q7 o. y* I: o( J/ a! c7_____0A9D
& x" F/ K" z7 W" I) j8_____1A1C: H. C4 I6 @/ S  U- n' O8 h* }6 `% p
9_____6D20
6 L  J9 J4 m; |: v$ W0_____1089) B/ c$ t2 _4 N" ^, l2 @. w, ~
a_____0F3E7 K! _) J% o% ]/ ?' v7 @: ?
b_____3159
, \- E" \$ v& `; yc_____3517
! `) S$ v6 o- v* t# E) `, ^d_____419C, M; [1 K2 A2 r9 o6 w5 p. x
e_____615C
' ~, \5 j- B+ C" K* U4 q+ Mf_____556F
' D3 _+ o" H7 h; A; l7 ?; u3 m# Gg_____2B7F6 X2 ?/ P/ k4 n: J1 a7 C
h_____0F9C
+ x! R! P& E0 \' c: Ki_____00FA3 C! V: S- _% \6 C5 i( v
j_____5A50
3 l5 {" M! S9 Xk_____2850! l  O( X7 a, [5 a/ N
l_____3E7B
* E; b/ Q0 Q& }: s1 j8 `' b' I& T9 [m_____71C5
) B( l( e; ]! x1 P" {+ ^n_____1FC8
5 A& v* |$ {0 p* d! j/ [* yo_____74C17 [4 q& m/ ~' [6 u! s. z: `, x
p_____5FB8$ f! S4 T% H. m' r6 `8 u
q_____6085
, V0 c1 d# V6 O$ i/ R2 yr_____3AC45 W0 g+ M- _: J" D
s_____2F50& I1 m1 a. G! r6 S/ @
t_____36F8  V# I% K6 Y. I) ?
u_____7010
# G2 Y1 b  l. G% w) ^0 u- B3 E6 Pv_____0B42. {5 v$ j' e# P
w_____1C7A& q# X+ X, |7 a+ D. a/ N' @; T
x_____16F8) T+ G& [+ V  x% I; T( s% o
y_____2EE7
( L3 e6 \/ U2 {. w( Tz_____5CF3
9 o6 Q; A  @4 _5 J4 f: n! V  z!_____6233
* x3 y8 i! K3 _" r; H@_____3A45* o8 {5 i2 q4 J3 V% d/ t, ^
#_____2291" y0 E! I9 W  f/ `
$_____5D5C
( S, S0 V+ p9 q! n1 Y%_____09B9
1 q& O& |2 j( k3 j^_____43EA" w+ X! E: Q2 l* S" P* q; R2 q
&_____62B9* m1 C1 A+ E5 b
*_____6301
8 D, X  U( j$ I6 e. C! M(_____4659
5 j$ U+ h0 [; y  {1 _( W)_____5C82
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