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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
( ^7 J4 X$ y+ P7 V$ d4 N原始出处:http://www.3ast.com.cm
: s1 M; ]/ B$ f9 x& {* N+ h. K F' I/ R& u7 J4 d: M5 v
看不懂的直接绕过
. o6 ]- e3 p( @加密前为:hwy123456
% ^8 m1 U3 l# l加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E/ c# e' o- S& V, y
$ X' e$ f& e: r) _& }" M7 i% L- C+ c============================================( t+ m* c2 h$ Z, k
上面是当时自己校内的心情。现在已经解破出来了,分享给大家* B' A/ C& E; _" s
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法7 l, I2 v* A: W6 w: r& f- V
以下是RSA算法文件
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文件名RSA.ASP/ t3 c) T. N8 R5 |0 t; @* g
===============================================$ d6 c! P9 M; p* f' n* R' S
<% 8 H( J' m4 |, `+ b H/ l
Class clsRSA * e( i$ \- t: i; E
Public PrivateKey w0 |& F6 A0 O
Public PublicKey . w+ Q [6 s: \" j! K- I$ J
Public Modulus
7 d5 F2 O( h5 a& y/ O8 ?# LPublic Function Crypt(pLngMessage, pLngKey)
9 g7 Z: _$ w/ q$ s4 v+ tOn Error Resume Next . s% q0 T; h5 `( H) K" |- {
Dim lLngMod + p3 x* c+ N$ w4 s
Dim lLngResult ! K' v, }' z/ j: M" C
Dim lLngIndex
5 ~- Y* J, y2 S# @' Y1 K* b! gIf pLngKey Mod 2 = 0 Then
/ A9 Q2 o" `8 E3 E$ UlLngResult = 1 ; E, b+ J1 n6 Y0 v
For lLngIndex = 1 To pLngKey / 2
; G( x7 i- H2 P- q3 Q6 o" U- OlLngMod = (pLngMessage ^ 2) Mod Modulus 4 y) n [/ ?( X/ _
' Mod may error on key generation " I8 Q( Y$ K5 D. g! g) j
lLngResult = (lLngMod * lLngResult) Mod Modulus 9 b% M7 A9 h G
If Err Then Exit Function & q8 p8 \8 d- c- U0 b) ]" X
Next
0 U5 [9 U$ ^7 y) uElse
7 `' V) C- i' G7 j8 xlLngResult = pLngMessage " e$ \, T/ t' g% N/ K
For lLngIndex = 1 To pLngKey / 2 3 J9 T5 P0 O+ S; G: s' p c0 ~
lLngMod = (pLngMessage ^ 2) Mod Modulus
f9 [1 S" a6 W4 G6 oOn Error Resume Next
3 j9 Z* A" H& V2 I' }" [- f' Mod may error on key generation / x1 b) c; [8 Z) `
lLngResult = (lLngMod * lLngResult) Mod Modulus
7 u# _; b! b. L% ?: D8 l$ [* IIf Err Then Exit Function
* n8 l+ q2 z& `2 _8 }8 m/ ZNext
5 e( y5 _# R t1 iEnd If
+ t' L9 [' a. M6 ?, |# O# @! gCrypt = lLngResult + p2 h. ~! v7 M: O% b
End Function
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+ c% J# k3 Q* T1 `Public Function Encode(ByVal pStrMessage)
% z! x0 H6 u$ DDim lLngIndex + X0 c$ \; X3 \6 Y3 E, _
Dim lLngMaxIndex
: q! W% J, W; E# z) B- rDim lBytAscii 0 M7 R" X4 w- p }8 B9 x+ s7 f
Dim lLngEncrypted
" t( Q7 o5 X+ T* ]) i+ O; i3 tlLngMaxIndex = Len(pStrMessage)
; ]* L5 v! I! Y" D: M5 f; gIf lLngMaxIndex = 0 Then Exit Function
; J; x* ?$ }9 j7 zFor lLngIndex = 1 To lLngMaxIndex
y. j4 Q. J5 B4 l9 ^1 ElBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) 2 A! V- L; V5 e$ i& ^3 J3 v
lLngEncrypted = Crypt(lBytAscii, PublicKey)
7 ?5 |9 `" y5 K! L8 HEncode = Encode & NumberToHex(lLngEncrypted, 4) * [8 K6 u/ X: X
Next 3 k, s9 b$ O" G- O" R5 m/ _
End Function v, Z) L7 V0 m6 |, Z% N E! a
Public Function Decode(ByVal pStrMessage)
; m5 v: J3 t, v& l$ [8 aDim lBytAscii
- _3 }9 l. n) M0 uDim lLngIndex 6 |, n9 N+ _# q2 j4 G2 I- o8 F
Dim lLngMaxIndex , F8 R) f" A- y& p! o+ Y' t
Dim lLngEncryptedData ^: |7 N# K6 r5 l* M
Decode = "" 5 J: i6 X3 R+ Q2 e. \: Z, I: N8 f
lLngMaxIndex = Len(pStrMessage) 8 m0 p' G, d% u% j
For lLngIndex = 1 To lLngMaxIndex Step 4 # H, E3 k. L! f, @9 ~8 U9 U
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
' H v& X7 V6 alBytAscii = Crypt(lLngEncryptedData, PrivateKey)
% o- i& O' P+ Y8 ?Decode = Decode & Chr(lBytAscii)
& S) i( b' {. G) nNext ; p' j0 |, h# R& L1 L7 o% P: @
End Function 0 ^+ \* y6 \, c& A' q+ M, k9 ?
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) 8 M4 {) C- S3 g4 K8 u, g. Q8 N
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
`5 |- p' N/ ]* b3 qEnd Function
. y% W! p, t: EPrivate Function HexToNumber(ByRef pStrHex) ?* R2 U3 {; A+ W) @$ N
HexToNumber = CLng("&h" & pStrHex) " r+ r% R s; z7 Y5 T
End Function
# b* i s7 V2 [: ]: Q7 g# |3 o5 VEnd Class ! {. I" ]2 Q4 E. v; T3 ?
function Encryptstr(Message) 4 j2 y# N1 Q% y9 T: P
Dim LngKeyE 8 m4 j5 E8 P; @2 {, s
Dim LngKeyD ! O& M7 y; g/ G7 \6 N
Dim LngKeyN
1 d3 X$ f! Z' j( s. f7 X+ jDim StrMessage
, K7 [$ J9 |% @- u7 K( c0 _7 LDim ObjRSA 0 T0 c9 O4 z/ ?* W: ?
LngKeyE = "32823"
5 P6 D% `- {+ ^; BLngKeyD = "20643" ; G7 x% N, g+ ]9 `: U
LngKeyN = "29893" ; D* X" b3 R9 \! [- z/ b- n
StrMessage = Message
- }4 `+ t4 B( O& E) I# U1 bSet ObjRSA = New clsRSA ' O/ |8 z$ b' q5 h# h' u
ObjRSA.PublicKey = LngKeyE " y! Q# J" S8 K3 h% O+ {1 ^
ObjRSA.Modulus = LngKeyN # f% \& j/ s, e( `' B9 i
Encryptstr = ObjRSA.Encode(StrMessage) 9 C+ ^' k$ l0 Y* X% L' n" f
Set ObjRSA = Nothing & F! h2 i* j$ [+ U8 ]4 Q
end function$ ]. j0 V# T9 [) {& s$ t
Function Decryptstr(Message) 2 |7 L$ g3 C, a' S8 q! m
Dim LngKeyE
* e7 S6 k3 h }3 pDim LngKeyD
2 w. Q; O- x* O. D( ?Dim LngKeyN
2 K1 H. a) [' ]6 u# g- xDim StrMessage 6 Y/ E. n1 v% o9 L E
Dim ObjRSA
# W, @( g7 @% O' uLngKeyE = "32823" ! K/ R. A% j0 q! X$ F% Y0 N4 ^' b
LngKeyD = "20643"
4 M% }+ y5 u& q3 C# qLngKeyN = "29893"
3 ~% H- [" b9 k' o% aStrMessage = Message . x5 [$ p4 X) b& x% y, ^, {
Set ObjRSA = New clsRSA 5 E% t3 Q# K1 L, N* U% L8 m# J5 E
ObjRSA.PrivateKey =LngKeyD
* a3 x n) ~( b% A$ @ObjRSA.Modulus=LngKeyN 9 J5 B/ O* L! w# X' L2 I
decryptstr=ObjRSA.Decode(StrMessage) # k' s" A' }. d' j$ p8 c+ L- M
Set ObjRSA = Nothing
. q+ N/ |% L" J- Y& C/ M ]end function
5 |9 N- g D5 b+ L%>
/ n; r6 U) M' i( f& c===============================================* i/ ?! O3 j# S% I x4 E( {3 d4 k
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还有一个用于测试这段代码的test.asp
5 K/ u, |$ h8 e1 g# N( C有兴趣的自己搭建个IIS测试下- {! Y& i- f! g$ i; Y0 T; {
<!--#INCLUDE FILE="RSA.asp"-->
. q4 d9 u4 q9 q% }( }6 S% ~<%
8 q! F9 U/ \3 _; { h5 v6 h7 \# {0 Gfunction Encryptstr(Message) $ [0 Y: _& W1 [ E, m% \: e
Dim LngKeyE
1 n$ |, y' R+ \) l; ADim LngKeyD % W; K& p3 ^4 }5 G [5 n( p
Dim LngKeyN
, w, v6 C$ e, ]- d4 f5 `) j- G' O! fDim StrMessage , z& r4 V3 B( m) \& a" b
Dim ObjRSA
7 m' I4 N* {6 ULngKeyE = "32823"
" u5 e# p. P6 n% Q5 [LngKeyD = "20643"
B" K9 B* h uLngKeyN = "29893"
' s# D5 ?# O3 g& GStrMessage = Message : _2 j! J9 h1 h1 i
Set ObjRSA = New clsRSA
7 {+ \/ L+ q0 e& sObjRSA.PublicKey = LngKeyE
- Z! X6 p% |( B, H6 mObjRSA.Modulus = LngKeyN ' E% T, G5 z1 ]
Encryptstr = ObjRSA.Encode(StrMessage) . O/ z% @4 \! ~; i; p
Set ObjRSA = Nothing 6 B$ L9 `- Z! l2 Z' M# k% W; x
end function
3 h3 Q3 V( z9 z% pfunction decryptstr(Message)
* R+ T) J( L2 Y# k. [- SDim LngKeyE
* z9 z9 P% o/ c+ p* n! `6 T( {Dim LngKeyD
5 T) ~+ E( K6 E0 w, mDim LngKeyN
$ _* {- [' z3 r" r" ^Dim StrMessage ( N/ t( ]7 j7 @5 q2 D% P) | Q: C# a
Dim ObjRSA
! _$ H4 ?! J5 i GLngKeyE = "32823" . c7 M$ M7 P6 f5 F E
LngKeyD = "20643" / @7 K6 s& J3 i% s; ]
LngKeyN = "29893" 9 j6 u( l D4 V6 Q1 D% `3 ]; Q8 T" A
StrMessage = Message & S$ w& |! @$ E! I
Set ObjRSA = New clsRSA : G8 S8 r, f5 m0 ^/ H
ObjRSA.PrivateKey =LngKeyD / Y" l+ z5 ~1 y% M/ [
ObjRSA.Modulus=LngKeyN
* h+ }7 L3 b# u, l: ?8 G! f) Ndecryptstr=ObjRSA.Decode(StrMessage) * T' p. Q2 t( H; r5 N" D$ n
Set ObjRSA = Nothing
5 P* g! t+ o# Y4 C8 Gend function 0 y4 g& E& ?5 n! E$ F' Y4 A
dim last,first . i/ @% T* Z0 e' C, c6 W# [
first="!@#$%^&*()"
' ~/ E4 y- F% T; b' PResponse.Write "加密前为:"&first + H m$ ]5 H& P! i* B
last=Encryptstr(first)
! t2 q( d1 \& k4 r1 g, j, R& o( MResponse.Write "加密后为"&last / I$ g$ l& y: z5 l" ?$ c: i
Response.Write "解密后为" &decryptstr(last) 3 ]& f, X5 U3 _
%> ==============================================) O# x& w* ~; t9 x6 W2 E+ I
剩下的就是字符的对照表了3 s: U- s) v E" p# V' V7 c
===================字符集================
6 k# O& |( `' X( q3 n2 H1_____6EBB
/ t) B" D; h9 s6 o2_____5C1F, X2 P5 \) O6 V6 B& i1 c5 N3 S8 N
3_____4D758 W* k5 x2 H+ i& @$ M% ?
4_____26CC7 ~, p3 V6 P) T# o: q
5_____4F88. V/ |: [3 t4 d o4 E
6_____3F4E* y; s, q7 ?- ]* J
7_____0A9D2 }0 u; [4 o( p0 G
8_____1A1C
( r% a. `4 x8 [0 _9_____6D20
: |3 X/ U3 \0 }0_____1089
. h( J' [* z! b+ b5 C/ Q3 G1 Oa_____0F3E
) X; `) x) ~% x D$ Ub_____3159$ U1 B# w% a* S4 h/ Z6 ~
c_____35173 C' W3 f* u+ N# J
d_____419C' O9 p/ J9 B0 E: K* n/ R% [6 f1 W- H
e_____615C
* ^2 F& A3 | u, ff_____556F
. {0 D- s" v5 ]; s5 k7 Q% k) L" ng_____2B7F. T/ m! M& u1 Q+ E& y4 C
h_____0F9C" r6 I( k/ N6 h
i_____00FA
2 n3 S4 R* s- r V- Jj_____5A50
) i; m. i; f$ k C, ek_____2850
0 N) \5 r# E) p" ul_____3E7B) r/ H# Z2 h' ]( u
m_____71C5 N& l" E- C: Z. b
n_____1FC8
/ ~% u/ o H8 U' ~o_____74C19 v; t- ?6 Z7 ^# ]/ [' G
p_____5FB8
7 `. \) ~ x. N! A$ a$ Tq_____6085$ {$ @2 ~! @( m5 n0 I7 a
r_____3AC4
5 j& O, S% y) v( P6 Z" {s_____2F50
* E' ]/ @% u% z6 |/ N& a) Z- st_____36F8
5 r% n6 | a O* du_____7010
$ b( {$ }! c/ J+ Q* S' |v_____0B42
* S1 G. o) A. S1 H- tw_____1C7A3 G- F% T" l O' s
x_____16F8
' U. r. l: d" R6 N4 b, T2 i& _y_____2EE7
' L1 v \ U$ r- Qz_____5CF3; F7 i9 N$ Z1 z q F/ w+ F
!_____62335 K; ]& f2 N& J; T; E/ z
@_____3A45
9 ?# ]( x4 Q, h5 d; B$ Q#_____2291) m2 c- ?8 }/ d5 N
$_____5D5C
8 m# \6 k( L+ y, }% ^8 L4 u$ N3 M%_____09B96 c# s" Z9 Z0 r
^_____43EA
% F5 q7 A, t6 n9 ]7 p5 w&_____62B9
" L* M' c; B' N6 c9 U*_____6301
. T, l. H4 |0 X7 N9 Z5 R(_____4659
- b. x6 K0 R p+ K# c)_____5C82 |
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