    
- 帖子
- 3852
- 积分
- 13044
- 威望
- 16780
- 金钱
- 36761
- 在线时间
- 1139 小时
         
|
原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
; i( }- E; J6 ]3 t) E原始出处:http://www.3ast.com.cm
. I& d/ g/ E* ]
7 @. ?4 B5 ~9 \0 [看不懂的直接绕过
+ M) h6 R: P% d. d2 Y加密前为:hwy123456
8 y- O" r6 v- z- i! s, @加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
: U% [4 E, B; }$ a" X! l* z3 z3 L* x% n% D0 A. l1 T T% L
============================================ {2 f" _% \1 B) p3 R/ u& s* Q
上面是当时自己校内的心情。现在已经解破出来了,分享给大家4 ]* h8 x( N$ `. z
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
# T+ a5 A6 {" A c8 d' Z+ l! N以下是RSA算法文件3 O9 b2 X* [; D% J' r! d/ ~
7 l" }% {. P, e2 M文件名RSA.ASP
$ T- {: \# b6 @' }0 ~0 Z* Q===============================================
$ W1 j( y! D% p4 d- m<% 0 x+ _3 @ s0 J% b
Class clsRSA
) W" w! g: N* U2 x% B- h8 U DPublic PrivateKey ) a B1 h. e7 \6 P
Public PublicKey
" b! {: U1 _, x: C7 W: y6 iPublic Modulus
' Y0 b, n- B8 e3 ^" t! w& lPublic Function Crypt(pLngMessage, pLngKey) ) {% x2 Z9 u' o) A; U) T6 V: D
On Error Resume Next % T2 V5 O' ~, S* U; Z# h
Dim lLngMod
7 \) q v) \( G s1 E( uDim lLngResult
) {2 G0 W2 b4 JDim lLngIndex 3 b5 s! ^' w; {+ J0 D; ` z6 X
If pLngKey Mod 2 = 0 Then , M c. U, V# D& b: B1 D
lLngResult = 1
4 z' {' ^! q6 T4 yFor lLngIndex = 1 To pLngKey / 2
) z1 i; B& f7 _1 J7 QlLngMod = (pLngMessage ^ 2) Mod Modulus + c8 P/ {- }4 g( q" N* L: E
' Mod may error on key generation 5 g( h2 v+ p6 p6 C4 ^. m( c
lLngResult = (lLngMod * lLngResult) Mod Modulus 9 ^) m0 @/ Y4 F3 O
If Err Then Exit Function
( y7 L5 a. ?7 u5 v' G; r9 ?Next 4 W$ K3 h5 u: ~ q1 y8 C- \9 W
Else
! I; f+ F r8 E8 z, r8 blLngResult = pLngMessage 6 a& n, i+ j+ P+ H K
For lLngIndex = 1 To pLngKey / 2
$ T! [! \& ~" o* alLngMod = (pLngMessage ^ 2) Mod Modulus
% S: V1 b3 {- @4 X mOn Error Resume Next 0 o: d5 z0 g, X
' Mod may error on key generation 9 H! w; l5 e ?) V3 l( T$ V1 T: T
lLngResult = (lLngMod * lLngResult) Mod Modulus
( o, C3 I* E( `3 Y5 D& B, QIf Err Then Exit Function 2 M5 K: X- h0 O0 ]8 s( ?% t) W
Next 4 H% D6 x& ]6 F3 X0 Z
End If 4 F( G% |2 b1 R [( ?$ d6 H% t3 n9 R
Crypt = lLngResult " u) u% O3 y) ?' @6 V
End Function6 @+ t& y; T5 k7 d
7 X; ^: f, \. X2 W' X: IPublic Function Encode(ByVal pStrMessage)
3 @; @ ~! i, b# |# tDim lLngIndex
; Q5 T# N) r: y: b& H) nDim lLngMaxIndex : q- l, w1 I6 a4 a* G7 O
Dim lBytAscii 4 v4 M3 J8 S* i( O4 j: r! H3 ]
Dim lLngEncrypted
3 k/ M) R4 o$ ?* }) _; \! K6 y5 UlLngMaxIndex = Len(pStrMessage) 2 S9 m3 m9 b/ U1 G
If lLngMaxIndex = 0 Then Exit Function + b9 t6 k: H3 ]; N9 {. H: @5 S" @
For lLngIndex = 1 To lLngMaxIndex 3 Z5 z0 s, E% }& l
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
" e+ A8 S2 x) z+ U( h+ s8 ]lLngEncrypted = Crypt(lBytAscii, PublicKey) " \" w+ F3 d1 U
Encode = Encode & NumberToHex(lLngEncrypted, 4) : B7 r/ f* V& q6 e2 Q7 s7 W$ U$ {
Next 2 R1 S# A3 \2 p% x# }' T5 t
End Function # P& {: u9 D: |" [8 r& y' v. V
Public Function Decode(ByVal pStrMessage) 5 S7 i+ {* Q0 J" m* n1 q$ X
Dim lBytAscii
% p }7 x1 P( g5 S: [* \5 M6 k9 BDim lLngIndex , L K% ?: I$ L
Dim lLngMaxIndex
' l% g0 m# m! S+ m+ b+ GDim lLngEncryptedData ' S! b* Q B( W7 l2 E/ a
Decode = "" 2 g' X2 E) B# O, T! H7 r' U T
lLngMaxIndex = Len(pStrMessage)
/ b' D, \; E, m. Y% CFor lLngIndex = 1 To lLngMaxIndex Step 4
+ G5 p7 l/ r. T9 i' @lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
$ D N0 e* ~+ x& \) ClBytAscii = Crypt(lLngEncryptedData, PrivateKey) ! R& c: Z- ?& r
Decode = Decode & Chr(lBytAscii)
9 {% ?5 U2 x2 w9 c$ mNext
1 ~/ u- i0 o' DEnd Function
# R* c, h/ J% H' R8 o0 n3 ]* {8 }) U! XPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) " c' M9 O, D% A+ m0 [
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
4 n) ^5 [( |( W) O+ q: ~# K. k' EEnd Function
; q! I6 q5 [+ @$ e7 APrivate Function HexToNumber(ByRef pStrHex) ! v/ Q! s+ i2 \1 O% [7 _' |
HexToNumber = CLng("&h" & pStrHex)
8 I7 V; \! R. V' VEnd Function 7 D8 a9 x3 ^$ Y' ~2 m
End Class 3 i+ T" d! L0 Q# G `) k9 L, X: T
function Encryptstr(Message)
) ^! e9 M' {! c2 e# S: B- _- VDim LngKeyE
4 k: q: j+ O8 q) Q, [) c/ m8 nDim LngKeyD
. Z1 a. f% [1 P! A3 O( VDim LngKeyN
* F: z, H9 _, k8 g* Z1 ADim StrMessage + O2 p! ~ b7 z
Dim ObjRSA
- a6 y0 h1 D+ W( lLngKeyE = "32823"
! d! z' ~1 S& W6 W9 i; ^LngKeyD = "20643"
0 p3 H) W+ ^/ y1 R! T3 ^LngKeyN = "29893"
: s' I$ z7 p% i* rStrMessage = Message 8 u* ~; S* @6 V# }4 o
Set ObjRSA = New clsRSA ; [9 I2 F. A/ f1 v6 H1 \
ObjRSA.PublicKey = LngKeyE
+ t9 ^6 }' b7 w1 t5 Q/ kObjRSA.Modulus = LngKeyN / [. x# R$ U. m0 z
Encryptstr = ObjRSA.Encode(StrMessage) / ?, g* |) _% i* K' f7 C3 ]4 d- d
Set ObjRSA = Nothing 3 I5 _9 |- s7 ~) }
end function( U g1 ~7 Q/ [* _/ S. v0 V8 p5 F1 g
Function Decryptstr(Message) + U; {* l3 u5 I
Dim LngKeyE : @3 V1 u2 w- y+ S- S9 K
Dim LngKeyD
8 G0 {/ C) Z0 ?& V* cDim LngKeyN ; Q h# d: L& U" W( J2 }& t- J, e
Dim StrMessage
' v4 a7 t3 l! k U r) TDim ObjRSA
4 S) m& ?' S$ d) E0 E% F8 o3 NLngKeyE = "32823" ; {, u" z' X+ P" f( V( m! V' H
LngKeyD = "20643"
% z: `! Y: ]$ K/ p2 p; ~LngKeyN = "29893"
9 `/ ]! H4 p8 u( r6 J3 a0 s% KStrMessage = Message
. h( a) z' b! D, |! pSet ObjRSA = New clsRSA
& a* {5 `+ e% }5 ^) A6 i1 ~ObjRSA.PrivateKey =LngKeyD
( A% [+ d3 b9 B! u! s) s7 SObjRSA.Modulus=LngKeyN
0 A( B2 ~' P, W! s. f1 udecryptstr=ObjRSA.Decode(StrMessage)
6 O6 d/ [4 [1 v% w$ ?5 ~. `6 pSet ObjRSA = Nothing
* _6 H1 P6 h4 ?- |end function 2 y9 v( z1 I9 F$ }7 \ r
%> Y5 L$ l. [/ Y2 e& _9 N- V% I
===============================================
9 p$ s. Q( s# \& W- S* W( s$ `3 v8 \" I1 L ]6 F7 d
还有一个用于测试这段代码的test.asp7 c$ V+ j6 y- P
有兴趣的自己搭建个IIS测试下) F: r- ] `& X W* m; p9 _0 c6 ?
<!--#INCLUDE FILE="RSA.asp"--> 1 n! @! T, B2 u
<%. ? Q- I, _4 b" `6 ?
function Encryptstr(Message) # { {" F- u* H9 y" q& I& p
Dim LngKeyE , t6 @# l- t! ]+ n* W9 W* k
Dim LngKeyD
# h. `; D& l( Q, P" z& I/ X9 [Dim LngKeyN 9 o+ e: w, Q+ l8 A, [
Dim StrMessage
4 W/ b; T9 N( q8 z2 f2 EDim ObjRSA
+ d/ v1 h5 L+ h1 \- g8 ILngKeyE = "32823" ' n) J: r# X+ M( l
LngKeyD = "20643" 4 u( P8 g" S+ h
LngKeyN = "29893"
; J2 e9 T% r% {StrMessage = Message 9 t: g- o; r# ~
Set ObjRSA = New clsRSA
( p* V# W: ^! P0 dObjRSA.PublicKey = LngKeyE M4 C8 A0 v+ G w
ObjRSA.Modulus = LngKeyN
. @; Y. E/ s* R, q1 F2 N8 o. I2 rEncryptstr = ObjRSA.Encode(StrMessage)
5 I9 X! r k2 Q- tSet ObjRSA = Nothing ; V( _% ^/ s0 d$ l& B
end function " O6 A6 b N1 W% e
function decryptstr(Message)
|8 \* s0 u( E, a, F d+ yDim LngKeyE
& U+ ~/ Q: S1 b* r8 ~3 j- ODim LngKeyD ) R& {3 o+ c0 b
Dim LngKeyN * L+ y0 W& A2 y
Dim StrMessage
: i, J! g) f/ ]Dim ObjRSA / k+ B7 S4 a* t7 n% J% F
LngKeyE = "32823" # X- B' I5 w6 O! y! E
LngKeyD = "20643" 7 x! y- q* J( L3 i) p" x! h
LngKeyN = "29893" ; G0 T9 S, Q* b6 \0 X* P3 |
StrMessage = Message
$ o8 J" I9 W1 N. c1 P+ eSet ObjRSA = New clsRSA
$ L6 G) z7 x, R- U l4 f4 q6 J* ?* qObjRSA.PrivateKey =LngKeyD
) w6 u2 a V+ p ~ObjRSA.Modulus=LngKeyN N3 @& b* R; N5 j$ \4 k' P
decryptstr=ObjRSA.Decode(StrMessage) 9 O- }' z; K8 z# y9 T
Set ObjRSA = Nothing 3 Q" J0 E8 Y' b' U
end function / p/ @: P. D0 p' v7 K" _
dim last,first
2 B) W5 S$ j, R/ N# cfirst="!@#$%^&*()"
# |- r! N z$ `6 d8 Z; D5 vResponse.Write "加密前为:"&first
! {+ e- h0 N) ?8 rlast=Encryptstr(first)
! \2 X/ s5 D/ G* |* c0 b4 \- FResponse.Write "加密后为"&last + k7 x, L; J) A/ o( P. |3 Q- Q
Response.Write "解密后为" &decryptstr(last) # t9 h, C5 r/ ~6 `
%> ==============================================1 c6 w; ^) y9 Y/ r9 B; T
剩下的就是字符的对照表了
# d0 J- l( J8 V( `& t; g===================字符集================5 B6 _5 L2 H! x
1_____6EBB7 i8 `* f: O$ T+ [9 K/ b
2_____5C1F
7 I" J5 y& J3 L- \3_____4D75# a9 z: |/ R& x, v* F% z) p; s
4_____26CC. ?* N4 U' K g3 ? ?4 b
5_____4F882 X6 E- o0 G1 m
6_____3F4E6 ~) B5 K+ U$ d, A j. ?& Z
7_____0A9D+ N. m+ F- L- Q" r6 o, } r
8_____1A1C. D& ^' t+ ?, G& g2 v) K
9_____6D20
1 o: m; ~6 Q) y) j+ { n$ {0_____1089& O) l0 j- U' u7 I
a_____0F3E3 ~% H* @) Y% l& N7 l" J- i$ K
b_____3159, W2 b/ N5 |/ A! [! \
c_____3517: u C$ u2 o5 o4 l* H1 b- M) a9 |) w5 I
d_____419C5 k1 o/ x, {* c0 c& y4 j
e_____615C
* ?+ C& N0 Z7 E; O7 j7 xf_____556F
" ~0 X! U1 w# Sg_____2B7F$ r: G) T$ p5 J/ [, D! u/ C
h_____0F9C4 {. g0 l$ } I3 k! w
i_____00FA
# n; U% e: h1 {* {" f6 U( Rj_____5A505 J& a+ S5 a% k+ }1 l: }* F
k_____28508 E" s9 O, I3 l H: `3 o( g P: m* k
l_____3E7B8 L$ q. ?% s5 a4 O
m_____71C5
7 Z% f9 P: J/ W2 bn_____1FC8
U' g" \) W/ k% B- ~& }! a+ A( to_____74C19 P l' G n* @2 n0 V' B. @) g8 W
p_____5FB8
# c) I) b0 ~) p2 b3 X g" p4 Nq_____6085
+ n% o# Y& P% n( G% wr_____3AC49 n& }: v$ L4 @; ^; a' X: T' Q \
s_____2F50! a) M2 g$ Q6 ]1 e
t_____36F8
* Y0 i7 `. ?1 Iu_____7010
3 O& Y' f7 d3 |% Y" P4 s, z, O9 }7 ev_____0B421 o3 R! l! j; s c# P
w_____1C7A
2 }5 k) I2 f4 y# T; J8 M4 W5 ax_____16F8) m' x. {7 Y) c0 }: `
y_____2EE7
9 w/ f! g) t! r0 R) b- C6 \8 `9 E4 qz_____5CF3
{! P( _* {% ~/ E0 g!_____6233
@6 S; X! _) F& A- ?@_____3A45
8 T2 g) k2 z' f; {8 d$ {, e8 e#_____2291& V# Q; v0 w. m
$_____5D5C
. b9 Z0 z3 l7 M- j, T%_____09B97 V" ?9 \3 ~+ L( ]7 w6 F* x2 i
^_____43EA
. B. H7 q$ S. M$ j6 ^& Y$ X&_____62B9
+ \ d4 A% }' I! R+ X0 g8 Z4 W*_____6301
4 m/ s; c7 w0 D/ X7 [5 \% A(_____46596 |1 X2 a% L6 V4 T, V- Z
)_____5C82 |
|